b^2-16b+55=0

Solution for b^2-16b+55=0 equation:

Simplifying
b2 + -16b + 55 = 0

Reorder the terms:
55 + -16b + b2 = 0

Solving
55 + -16b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(5 + -1b)(11 + -1b) = 0

Subproblem 1
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Subproblem 2
Set the factor '(11 + -1b)' equal to zero and attempt to solve:

Simplifying
11 + -1b = 0

Solving
11 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -1b = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -1b = 0 + -11
-1b = 0 + -11

Combine like terms: 0 + -11 = -11
-1b = -11

Divide each side by '-1'.
b = 11

Simplifying
b = 11
Solution
b = {5, 11}